(9x-5+10x-2)/2=27x+3

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Solution for (9x-5+10x-2)/2=27x+3 equation:



(9x-5+10x-2)/2=27x+3
We move all terms to the left:
(9x-5+10x-2)/2-(27x+3)=0
We add all the numbers together, and all the variables
(19x-7)/2-(27x+3)=0
We get rid of parentheses
(19x-7)/2-27x-3=0
We multiply all the terms by the denominator
(19x-7)-27x*2-3*2=0
We add all the numbers together, and all the variables
(19x-7)-27x*2-6=0
Wy multiply elements
(19x-7)-54x-6=0
We get rid of parentheses
19x-54x-7-6=0
We add all the numbers together, and all the variables
-35x-13=0
We move all terms containing x to the left, all other terms to the right
-35x=13
x=13/-35
x=-13/35

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