3x+5(4-2x)=2(x-8)

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Solution for 3x+5(4-2x)=2(x-8) equation: 



3x+5(4-2x)=2(x-8)

We move all terms to the left:

3x+5(4-2x)-(2(x-8))=0

We add all the numbers together, and all the variables

3x+5(-2x+4)-(2(x-8))=0

We multiply parentheses

3x-10x-(2(x-8))+20=0



We calculate terms in parentheses: -(2(x-8)), so:

2(x-8)

We multiply parentheses

2x-16

Back to the equation:

-(2x-16)



We add all the numbers together, and all the variables

-7x-(2x-16)+20=0

We get rid of parentheses

-7x-2x+16+20=0

We add all the numbers together, and all the variables

-9x+36=0

We move all terms containing x to the left, all other terms to the right

-9x=-36

x=-36/-9

x=+4

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