3x+47+(x+26)=(27+x)+10

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Solution for 3x+47+(x+26)=(27+x)+10 equation: 



3x+47+(x+26)=(27+x)+10

We move all terms to the left:

3x+47+(x+26)-((27+x)+10)=0

We add all the numbers together, and all the variables

3x+(x+26)-((x+27)+10)+47=0

We get rid of parentheses

3x+x-((x+27)+10)+26+47=0



We calculate terms in parentheses: -((x+27)+10), so:

(x+27)+10

We get rid of parentheses

x+27+10

We add all the numbers together, and all the variables

x+37

Back to the equation:

-(x+37)



We add all the numbers together, and all the variables

4x-(x+37)+73=0

We get rid of parentheses

4x-x-37+73=0

We add all the numbers together, and all the variables

3x+36=0

We move all terms containing x to the left, all other terms to the right

3x=-36

x=-36/3

x=-12

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