28=(7y-4)+7y-5

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Solution for 28=(7y-4)+7y-5 equation: 



28=(7y-4)+7y-5

We move all terms to the left:

28-((7y-4)+7y-5)=0



We calculate terms in parentheses: -((7y-4)+7y-5), so:

(7y-4)+7y-5

We add all the numbers together, and all the variables

7y+(7y-4)-5

We get rid of parentheses

7y+7y-4-5

We add all the numbers together, and all the variables

14y-9

Back to the equation:

-(14y-9)



We get rid of parentheses

-14y+9+28=0

We add all the numbers together, and all the variables

-14y+37=0

We move all terms containing y to the left, all other terms to the right

-14y=-37

y=-37/-14

y=2+9/14

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