28=(7y-4)+(7y+5)

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Solution for 28=(7y-4)+(7y+5) equation: 



28=(7y-4)+(7y+5)

We move all terms to the left:

28-((7y-4)+(7y+5))=0



We calculate terms in parentheses: -((7y-4)+(7y+5)), so:

(7y-4)+(7y+5)

We get rid of parentheses

7y+7y-4+5

We add all the numbers together, and all the variables

14y+1

Back to the equation:

-(14y+1)



We get rid of parentheses

-14y-1+28=0

We add all the numbers together, and all the variables

-14y+27=0

We move all terms containing y to the left, all other terms to the right

-14y=-27

y=-27/-14

y=1+13/14

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