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3x+3(5x/7x)=12-x
We move all terms to the left:
3x+3(5x/7x)-(12-x)=0
Domain of the equation: 7x)!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
3x+3(+5x/7x)-(-1x+12)=0
We multiply parentheses
3x+15x-(-1x+12)=0
We get rid of parentheses
3x+15x+1x-12=0
We add all the numbers together, and all the variables
19x-12=0
We move all terms containing x to the left, all other terms to the right
19x=12
x=12/19
x=12/19
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