8+2(6u-7)=-2(7u-5)+8u

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Solution for 8+2(6u-7)=-2(7u-5)+8u equation: 



8+2(6u-7)=-2(7u-5)+8u

We move all terms to the left:

8+2(6u-7)-(-2(7u-5)+8u)=0

We multiply parentheses

12u-(-2(7u-5)+8u)-14+8=0



We calculate terms in parentheses: -(-2(7u-5)+8u), so:

-2(7u-5)+8u

We add all the numbers together, and all the variables

8u-2(7u-5)

We multiply parentheses

8u-14u+10

We add all the numbers together, and all the variables

-6u+10

Back to the equation:

-(-6u+10)



We add all the numbers together, and all the variables

12u-(-6u+10)-6=0

We get rid of parentheses

12u+6u-10-6=0

We add all the numbers together, and all the variables

18u-16=0

We move all terms containing u to the left, all other terms to the right

18u=16

u=16/18

u=8/9

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