6(x+2)=(9x)-21

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Solution for 6(x+2)=(9x)-21 equation: 



6(x+2)=(9x)-21

We move all terms to the left:

6(x+2)-((9x)-21)=0

We multiply parentheses

6x-(9x-21)+12=0

We get rid of parentheses

6x-9x+21+12=0

We add all the numbers together, and all the variables

-3x+33=0

We move all terms containing x to the left, all other terms to the right

-3x=-33

x=-33/-3

x=+11

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