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3x+2=8-3(2-x)
We move all terms to the left:
3x+2-(8-3(2-x))=0
We add all the numbers together, and all the variables
3x-(8-3(-1x+2))+2=0
We calculate terms in parentheses: -(8-3(-1x+2)), so:We get rid of parentheses
8-3(-1x+2)
determiningTheFunctionDomain -3(-1x+2)+8
We multiply parentheses
3x-6+8
We add all the numbers together, and all the variables
3x+2
Back to the equation:
-(3x+2)
3x-3x-2+2=0
We add all the numbers together, and all the variables
=0
x=0/1
x=0
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