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2x+(x+4)=(x-3)+(x-3)
We move all terms to the left:
2x+(x+4)-((x-3)+(x-3))=0
We get rid of parentheses
2x+x-((x-3)+(x-3))+4=0
We calculate terms in parentheses: -((x-3)+(x-3)), so:We add all the numbers together, and all the variables
(x-3)+(x-3)
We get rid of parentheses
x+x-3-3
We add all the numbers together, and all the variables
2x-6
Back to the equation:
-(2x-6)
3x-(2x-6)+4=0
We get rid of parentheses
3x-2x+6+4=0
We add all the numbers together, and all the variables
x+10=0
We move all terms containing x to the left, all other terms to the right
x=-10
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