4(a-4)=3(3a+5)

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Solution for 4(a-4)=3(3a+5) equation: 



4(a-4)=3(3a+5)

We move all terms to the left:

4(a-4)-(3(3a+5))=0

We multiply parentheses

4a-(3(3a+5))-16=0



We calculate terms in parentheses: -(3(3a+5)), so:

3(3a+5)

We multiply parentheses

9a+15

Back to the equation:

-(9a+15)



We get rid of parentheses

4a-9a-15-16=0

We add all the numbers together, and all the variables

-5a-31=0

We move all terms containing a to the left, all other terms to the right

-5a=31

a=31/-5

a=-6+1/5

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