3(x-5)+5(x-3)=4(x-2)-3(x+1)-7

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Solution for 3(x-5)+5(x-3)=4(x-2)-3(x+1)-7 equation: 



3(x-5)+5(x-3)=4(x-2)-3(x+1)-7

We move all terms to the left:

3(x-5)+5(x-3)-(4(x-2)-3(x+1)-7)=0

We multiply parentheses

3x+5x-(4(x-2)-3(x+1)-7)-15-15=0



We calculate terms in parentheses: -(4(x-2)-3(x+1)-7), so:

4(x-2)-3(x+1)-7

We multiply parentheses

4x-3x-8-3-7

We add all the numbers together, and all the variables

x-18

Back to the equation:

-(x-18)



We add all the numbers together, and all the variables

8x-(x-18)-30=0

We get rid of parentheses

8x-x+18-30=0

We add all the numbers together, and all the variables

7x-12=0

We move all terms containing x to the left, all other terms to the right

7x=12

x=12/7

x=1+5/7

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