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3x+2=5x(1)
We move all terms to the left:
3x+2-(5x(1))=0
determiningTheFunctionDomain 3x-5x1+2=0
We add all the numbers together, and all the variables
-2x+2=0
We move all terms containing x to the left, all other terms to the right
-2x=-2
x=-2/-2
x=1
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