4x+26+2(x-3)=128

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Solution for 4x+26+2(x-3)=128 equation: 



4x+26+2(x-3)=128

We move all terms to the left:

4x+26+2(x-3)-(128)=0

We add all the numbers together, and all the variables

4x+2(x-3)-102=0

We multiply parentheses

4x+2x-6-102=0

We add all the numbers together, and all the variables

6x-108=0

We move all terms containing x to the left, all other terms to the right

6x=108

x=108/6

x=18

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