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7+2(5x+3)=-3-5(2x+2)
We move all terms to the left:
7+2(5x+3)-(-3-5(2x+2))=0
We multiply parentheses
10x-(-3-5(2x+2))+6+7=0
We calculate terms in parentheses: -(-3-5(2x+2)), so:We add all the numbers together, and all the variables
-3-5(2x+2)
determiningTheFunctionDomain -5(2x+2)-3
We multiply parentheses
-10x-10-3
We add all the numbers together, and all the variables
-10x-13
Back to the equation:
-(-10x-13)
10x-(-10x-13)+13=0
We get rid of parentheses
10x+10x+13+13=0
We add all the numbers together, and all the variables
20x+26=0
We move all terms containing x to the left, all other terms to the right
20x=-26
x=-26/20
x=-1+3/10
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