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3x+2=3x^2
We move all terms to the left:
3x+2-(3x^2)=0
determiningTheFunctionDomain -3x^2+3x+2=0
a = -3; b = 3; c = +2;
Δ = b2-4ac
Δ = 32-4·(-3)·2
Δ = 33
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-\sqrt{33}}{2*-3}=\frac{-3-\sqrt{33}}{-6} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+\sqrt{33}}{2*-3}=\frac{-3+\sqrt{33}}{-6} $
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