3(c-3)=2(c-6)

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Solution for 3(c-3)=2(c-6) equation: 



3(c-3)=2(c-6)

We move all terms to the left:

3(c-3)-(2(c-6))=0

We multiply parentheses

3c-(2(c-6))-9=0



We calculate terms in parentheses: -(2(c-6)), so:

2(c-6)

We multiply parentheses

2c-12

Back to the equation:

-(2c-12)



We get rid of parentheses

3c-2c+12-9=0

We add all the numbers together, and all the variables

c+3=0

We move all terms containing c to the left, all other terms to the right

c=-3

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