3x+2(x+1)=10+7(x-2)

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Solution for 3x+2(x+1)=10+7(x-2) equation: 



3x+2(x+1)=10+7(x-2)

We move all terms to the left:

3x+2(x+1)-(10+7(x-2))=0

We multiply parentheses

3x+2x-(10+7(x-2))+2=0



We calculate terms in parentheses: -(10+7(x-2)), so:

10+7(x-2)

determiningTheFunctionDomain
7(x-2)+10

We multiply parentheses

7x-14+10

We add all the numbers together, and all the variables

7x-4

Back to the equation:

-(7x-4)



We add all the numbers together, and all the variables

5x-(7x-4)+2=0

We get rid of parentheses

5x-7x+4+2=0

We add all the numbers together, and all the variables

-2x+6=0

We move all terms containing x to the left, all other terms to the right

-2x=-6

x=-6/-2

x=+3

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