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(2x+7)(x+8)=6x+3
We move all terms to the left:
(2x+7)(x+8)-(6x+3)=0
We get rid of parentheses
(2x+7)(x+8)-6x-3=0
We multiply parentheses ..
(+2x^2+16x+7x+56)-6x-3=0
We get rid of parentheses
2x^2+16x+7x-6x+56-3=0
We add all the numbers together, and all the variables
2x^2+17x+53=0
a = 2; b = 17; c = +53;
Δ = b2-4ac
Δ = 172-4·2·53
Δ = -135
Delta is less than zero, so there is no solution for the equation
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