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2.5x^2+12.5x-60=0
a = 2.5; b = 12.5; c = -60;
Δ = b2-4ac
Δ = 12.52-4·2.5·(-60)
Δ = 756.25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(12.5)-\sqrt{756.25}}{2*2.5}=\frac{-12.5-\sqrt{756.25}}{5} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(12.5)+\sqrt{756.25}}{2*2.5}=\frac{-12.5+\sqrt{756.25}}{5} $
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