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3x+10-x=2(x+5)
We move all terms to the left:
3x+10-x-(2(x+5))=0
We add all the numbers together, and all the variables
2x-(2(x+5))+10=0
We calculate terms in parentheses: -(2(x+5)), so:We get rid of parentheses
2(x+5)
We multiply parentheses
2x+10
Back to the equation:
-(2x+10)
2x-2x-10+10=0
We add all the numbers together, and all the variables
=0
x=0/1
x=0
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