4-(n-20)=6(n+3)

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Solution for 4-(n-20)=6(n+3) equation: 



4-(n-20)=6(n+3)

We move all terms to the left:

4-(n-20)-(6(n+3))=0

We get rid of parentheses

-n-(6(n+3))+20+4=0



We calculate terms in parentheses: -(6(n+3)), so:

6(n+3)

We multiply parentheses

6n+18

Back to the equation:

-(6n+18)



We add all the numbers together, and all the variables

-1n-(6n+18)+24=0

We get rid of parentheses

-1n-6n-18+24=0

We add all the numbers together, and all the variables

-7n+6=0

We move all terms containing n to the left, all other terms to the right

-7n=-6

n=-6/-7

n=6/7

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