3x+97=7(4x-13)-2x(9x-3)

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Solution for 3x+97=7(4x-13)-2x(9x-3) equation: 



3x+97=7(4x-13)-2x(9x-3)

We move all terms to the left:

3x+97-(7(4x-13)-2x(9x-3))=0



We calculate terms in parentheses: -(7(4x-13)-2x(9x-3)), so:

7(4x-13)-2x(9x-3)

We multiply parentheses

-18x^2+28x+6x-91

We add all the numbers together, and all the variables

-18x^2+34x-91

Back to the equation:

-(-18x^2+34x-91)



We get rid of parentheses

18x^2-34x+3x+91+97=0

We add all the numbers together, and all the variables

18x^2-31x+188=0

a = 18; b = -31; c = +188;
Δ = b2-4ac
Δ = -312-4·18·188
Δ = -12575
Delta is less than zero, so there is no solution for the equation

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