3x+(x+20)+(x+30)+50=300

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Solution for 3x+(x+20)+(x+30)+50=300 equation: 



3x+(x+20)+(x+30)+50=300

We move all terms to the left:

3x+(x+20)+(x+30)+50-(300)=0

We add all the numbers together, and all the variables

3x+(x+20)+(x+30)-250=0

We get rid of parentheses

3x+x+x+20+30-250=0

We add all the numbers together, and all the variables

5x-200=0

We move all terms containing x to the left, all other terms to the right

5x=200

x=200/5

x=40

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