(3x+13)+(2x+2)=(9x-13)

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Solution for (3x+13)+(2x+2)=(9x-13) equation: 



(3x+13)+(2x+2)=(9x-13)

We move all terms to the left:

(3x+13)+(2x+2)-((9x-13))=0

We get rid of parentheses

3x+2x-((9x-13))+13+2=0



We calculate terms in parentheses: -((9x-13)), so:

(9x-13)

We get rid of parentheses

9x-13

Back to the equation:

-(9x-13)



We add all the numbers together, and all the variables

5x-(9x-13)+15=0

We get rid of parentheses

5x-9x+13+15=0

We add all the numbers together, and all the variables

-4x+28=0

We move all terms containing x to the left, all other terms to the right

-4x=-28

x=-28/-4

x=+7

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