(3x+16)+(4x-15)=(2x+8)

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Solution for (3x+16)+(4x-15)=(2x+8) equation: 



(3x+16)+(4x-15)=(2x+8)

We move all terms to the left:

(3x+16)+(4x-15)-((2x+8))=0

We get rid of parentheses

3x+4x-((2x+8))+16-15=0



We calculate terms in parentheses: -((2x+8)), so:

(2x+8)

We get rid of parentheses

2x+8

Back to the equation:

-(2x+8)



We add all the numbers together, and all the variables

7x-(2x+8)+1=0

We get rid of parentheses

7x-2x-8+1=0

We add all the numbers together, and all the variables

5x-7=0

We move all terms containing x to the left, all other terms to the right

5x=7

x=7/5

x=1+2/5

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