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3x*3x+2x-7=0
We add all the numbers together, and all the variables
2x+3x*3x-7=0
Wy multiply elements
9x^2+2x-7=0
a = 9; b = 2; c = -7;
Δ = b2-4ac
Δ = 22-4·9·(-7)
Δ = 256
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{256}=16$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-16}{2*9}=\frac{-18}{18} =-1 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+16}{2*9}=\frac{14}{18} =7/9 $
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