.6(2x+1/3)=3(0.3x+(-3))+2

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Solution for .6(2x+1/3)=3(0.3x+(-3))+2 equation: 



.6(2x+1/3)=3(0.3x+(-3))+2

We move all terms to the left:

.6(2x+1/3)-(3(0.3x+(-3))+2)=0

We add all the numbers together, and all the variables

.6(+2x+1/3)-(3(0.3x+(-3))+2)=0

We multiply parentheses

1.2x-(3(0.3x+(-3))+2)+1/3*0.6=0

We multiply all the terms by the denominator


(1.2x)*3*0.6-((3(0.3x+(-3))+2))*3*0.6+1=0

We add all the numbers together, and all the variables

(+1.2x)*3*0.6-((3(0.3x+(-3))+2))*3*0.6+1=0

We move all terms containing x to the left, all other terms to the right

(+1.2x)*3*0.6-((3(0.3x+(-3))+2))*3*0.6=-1

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