(2-w)(4w+9)=0

Solution for (2-w)(4w+9)=0 equation:

(2-w)(4w+9)=0

We add all the numbers together, and all the variables

(-1w+2)(4w+9)=0

We multiply parentheses ..

(-4w^2-9w+8w+18)=0

We get rid of parentheses

-4w^2-9w+8w+18=0

We add all the numbers together, and all the variables

-4w^2-1w+18=0

a = -4; b = -1; c = +18;
Δ = b2-4ac
Δ = -12-4·(-4)·18
Δ = 289
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{289}=17$
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-17}{2*-4}=\frac{-16}{-8}
=+2
$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+17}{2*-4}=\frac{18}{-8}
=-2+1/4
$