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3x(6x+2)=6(2x)+4
We move all terms to the left:
3x(6x+2)-(6(2x)+4)=0
We multiply parentheses
18x^2+6x-(62x+4)=0
We get rid of parentheses
18x^2+6x-62x-4=0
We add all the numbers together, and all the variables
18x^2-56x-4=0
a = 18; b = -56; c = -4;
Δ = b2-4ac
Δ = -562-4·18·(-4)
Δ = 3424
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{3424}=\sqrt{16*214}=\sqrt{16}*\sqrt{214}=4\sqrt{214}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-56)-4\sqrt{214}}{2*18}=\frac{56-4\sqrt{214}}{36} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-56)+4\sqrt{214}}{2*18}=\frac{56+4\sqrt{214}}{36} $
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