0.2x(x-20)=44-x

Solution for 0.2x(x-20)=44-x equation:

0.2x(x-20)=44-x

We move all terms to the left:

0.2x(x-20)-(44-x)=0

We add all the numbers together, and all the variables

0.2x(x-20)-(-1x+44)=0

We multiply parentheses

0x^2+0x-(-1x+44)=0

We get rid of parentheses

0x^2+0x+1x-44=0

We add all the numbers together, and all the variables

x^2+2x-44=0

a = 1; b = 2; c = -44;
Δ = b2-4ac
Δ = 22-4·1·(-44)
Δ = 180
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{180}=\sqrt{36*5}=\sqrt{36}*\sqrt{5}=6\sqrt{5}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-6\sqrt{5}}{2*1}=\frac{-2-6\sqrt{5}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+6\sqrt{5}}{2*1}=\frac{-2+6\sqrt{5}}{2}
$