3x(5x+4)+4(-5+4x)=6(5x-5)-6

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Solution for 3x(5x+4)+4(-5+4x)=6(5x-5)-6 equation: 



3x(5x+4)+4(-5+4x)=6(5x-5)-6

We move all terms to the left:

3x(5x+4)+4(-5+4x)-(6(5x-5)-6)=0

We add all the numbers together, and all the variables

3x(5x+4)+4(4x-5)-(6(5x-5)-6)=0

We multiply parentheses

15x^2+12x+16x-(6(5x-5)-6)-20=0



We calculate terms in parentheses: -(6(5x-5)-6), so:

6(5x-5)-6

We multiply parentheses

30x-30-6

We add all the numbers together, and all the variables

30x-36

Back to the equation:

-(30x-36)



We add all the numbers together, and all the variables

15x^2+28x-(30x-36)-20=0

We get rid of parentheses

15x^2+28x-30x+36-20=0

We add all the numbers together, and all the variables

15x^2-2x+16=0

a = 15; b = -2; c = +16;
Δ = b2-4ac
Δ = -22-4·15·16
Δ = -956
Delta is less than zero, so there is no solution for the equation

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