3(k-6)-(2k-7)=8

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Solution for 3(k-6)-(2k-7)=8 equation: 



3(k-6)-(2k-7)=8

We move all terms to the left:

3(k-6)-(2k-7)-(8)=0

We multiply parentheses

3k-(2k-7)-18-8=0

We get rid of parentheses

3k-2k+7-18-8=0

We add all the numbers together, and all the variables

k-19=0

We move all terms containing k to the left, all other terms to the right

k=19

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