Q(2x+1)=4-3(2x+1)

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Solution for Q(2x+1)=4-3(2x+1) equation: 



(2Q+1)=4-3(2Q+1)

We move all terms to the left:

(2Q+1)-(4-3(2Q+1))=0

We get rid of parentheses

2Q-(4-3(2Q+1))+1=0



We calculate terms in parentheses: -(4-3(2Q+1)), so:

4-3(2Q+1)

determiningTheFunctionDomain
-3(2Q+1)+4

We multiply parentheses

-6Q-3+4

We add all the numbers together, and all the variables

-6Q+1

Back to the equation:

-(-6Q+1)



We get rid of parentheses

2Q+6Q-1+1=0

We add all the numbers together, and all the variables

8Q=0

Q=0/8

Q=0

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