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3x(2x+7)=136
We move all terms to the left:
3x(2x+7)-(136)=0
We multiply parentheses
6x^2+21x-136=0
a = 6; b = 21; c = -136;
Δ = b2-4ac
Δ = 212-4·6·(-136)
Δ = 3705
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(21)-\sqrt{3705}}{2*6}=\frac{-21-\sqrt{3705}}{12} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(21)+\sqrt{3705}}{2*6}=\frac{-21+\sqrt{3705}}{12} $
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