2x+1/5x-1=4x+1/10x-4

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Solution for 2x+1/5x-1=4x+1/10x-4 equation: 



2x+1/5x-1=4x+1/10x-4

We move all terms to the left:

2x+1/5x-1-(4x+1/10x-4)=0



Domain of the equation: 5x!=0

x!=0/5

x!=0

x∈R





Domain of the equation: 10x-4)!=0

x∈R



We get rid of parentheses

2x+1/5x-4x-1/10x+4-1=0

We calculate fractions


2x-4x+10x/50x^2+(-5x)/50x^2+4-1=0

We add all the numbers together, and all the variables

-2x+10x/50x^2+(-5x)/50x^2+3=0

We multiply all the terms by the denominator


-2x*50x^2+10x+(-5x)+3*50x^2=0

We add all the numbers together, and all the variables

10x-2x*50x^2+(-5x)+3*50x^2=0

Wy multiply elements

-100x^3+150x^2+10x+(-5x)=0

We get rid of parentheses

-100x^3+150x^2+10x-5x=0

We do not support expression: x^3

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