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3k+12/2=9
We move all terms to the left:
3k+12/2-(9)=0
determiningTheFunctionDomain 3k-9+12/2=0
We add all the numbers together, and all the variables
3k-3=0
We move all terms containing k to the left, all other terms to the right
3k=3
k=3/3
k=1
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