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12m^2+5m-13=0
a = 12; b = 5; c = -13;
Δ = b2-4ac
Δ = 52-4·12·(-13)
Δ = 649
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5)-\sqrt{649}}{2*12}=\frac{-5-\sqrt{649}}{24} $$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5)+\sqrt{649}}{2*12}=\frac{-5+\sqrt{649}}{24} $
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