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(G)=2G^2+3G+1
We move all terms to the left:
(G)-(2G^2+3G+1)=0
We get rid of parentheses
-2G^2+G-3G-1=0
We add all the numbers together, and all the variables
-2G^2-2G-1=0
a = -2; b = -2; c = -1;
Δ = b2-4ac
Δ = -22-4·(-2)·(-1)
Δ = -4
Delta is less than zero, so there is no solution for the equation
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