3a-5=4(3a+1)=15

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Solution for 3a-5=4(3a+1)=15 equation:



3a-5=4(3a+1)=15
We move all terms to the left:
3a-5-(4(3a+1))=0
We calculate terms in parentheses: -(4(3a+1)), so:
4(3a+1)
We multiply parentheses
12a+4
Back to the equation:
-(12a+4)
We get rid of parentheses
3a-12a-4-5=0
We add all the numbers together, and all the variables
-9a-9=0
We move all terms containing a to the left, all other terms to the right
-9a=9
a=9/-9
a=-1

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