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3(1x-3)=1x-19
We move all terms to the left:
3(1x-3)-(1x-19)=0
We add all the numbers together, and all the variables
3(x-3)-(x-19)=0
We multiply parentheses
3x-(x-19)-9=0
We get rid of parentheses
3x-x+19-9=0
We add all the numbers together, and all the variables
2x+10=0
We move all terms containing x to the left, all other terms to the right
2x=-10
x=-10/2
x=-5
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