3=18+(1/44)n

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Solution for 3=18+(1/44)n equation: 



3=18+(1/44)n

We move all terms to the left:

3-(18+(1/44)n)=0



Domain of the equation: 44)n)!=0

n!=0/1

n!=0

n∈R



We add all the numbers together, and all the variables

-(18+(+1/44)n)+3=0

We multiply all the terms by the denominator


-(18+(+1+3*44)n)=0



We calculate terms in parentheses: -(18+(+1+3*44)n), so:

18+(+1+3*44)n

determiningTheFunctionDomain
(+1+3*44)n+18

We add all the numbers together, and all the variables

133n+18

Back to the equation:

-(133n+18)



We get rid of parentheses

-133n-18=0

We move all terms containing n to the left, all other terms to the right

-133n=18

n=18/-133

n=-18/133

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