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2(x+)+x=3(x+2)-2
We move all terms to the left:
2(x+)+x-(3(x+2)-2)=0
We add all the numbers together, and all the variables
2(+x)+x-(3(x+2)-2)=0
We add all the numbers together, and all the variables
x+2(+x)-(3(x+2)-2)=0
We multiply parentheses
x+2x-(3(x+2)-2)=0
We calculate terms in parentheses: -(3(x+2)-2), so:We add all the numbers together, and all the variables
3(x+2)-2
We multiply parentheses
3x+6-2
We add all the numbers together, and all the variables
3x+4
Back to the equation:
-(3x+4)
3x-(3x+4)=0
We get rid of parentheses
3x-3x-4=0
We add all the numbers together, and all the variables
-4!=0
There is no solution for this equation
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