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3=(1/44)n
We move all terms to the left:
3-((1/44)n)=0
Domain of the equation: 44)n)!=0We add all the numbers together, and all the variables
n!=0/1
n!=0
n∈R
-((+1/44)n)+3=0
We multiply all the terms by the denominator
-((+1+3*44)n)=0
We calculate terms in parentheses: -((+1+3*44)n), so:n=0/-133
(+1+3*44)n
We add all the numbers together, and all the variables
133n
Back to the equation:
-(133n)
n=0
Równanie nie ma rozwiązania
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