38=2(2x-5)+2x

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Solution for 38=2(2x-5)+2x equation: 



38=2(2x-5)+2x

We move all terms to the left:

38-(2(2x-5)+2x)=0



We calculate terms in parentheses: -(2(2x-5)+2x), so:

2(2x-5)+2x

We add all the numbers together, and all the variables

2x+2(2x-5)

We multiply parentheses

2x+4x-10

We add all the numbers together, and all the variables

6x-10

Back to the equation:

-(6x-10)



We get rid of parentheses

-6x+10+38=0

We add all the numbers together, and all the variables

-6x+48=0

We move all terms containing x to the left, all other terms to the right

-6x=-48

x=-48/-6

x=+8

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