(3/4)X+2-3x=6

Solution for (3/4)X+2-3x=6 equation:

(3/4)X+2-3X=6

We move all terms to the left:

(3/4)X+2-3X-(6)=0


Domain of the equation: 4)X!=0

X!=0/1

X!=0

X∈R


We add all the numbers together, and all the variables

(+3/4)X-3X+2-6=0

We add all the numbers together, and all the variables

-3X+(+3/4)X-4=0

We multiply parentheses

3X^2-3X-4=0

a = 3; b = -3; c = -4;
Δ = b2-4ac
Δ = -32-4·3·(-4)
Δ = 57
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-3)-\sqrt{57}}{2*3}=\frac{3-\sqrt{57}}{6}
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-3)+\sqrt{57}}{2*3}=\frac{3+\sqrt{57}}{6}
$