.01(x+12)-0.12=0.01(7x+12)

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Solution for .01(x+12)-0.12=0.01(7x+12) equation: 



.01(x+12)-0.12=0.01(7x+12)

We move all terms to the left:

.01(x+12)-0.12-(0.01(7x+12))=0

We multiply parentheses

0.01x-(0.01(7x+12))+0.12-0.12=0



We calculate terms in parentheses: -(0.01(7x+12)), so:

0.01(7x+12)

We multiply parentheses

0.07x+0.12

Back to the equation:

-(0.07x+0.12)



We add all the numbers together, and all the variables

0.01x-(0.07x+0.12)=0

We get rid of parentheses

0.01x-0.07x-0.12=0

We add all the numbers together, and all the variables

-0.06x-0.12=0

We move all terms containing x to the left, all other terms to the right

-0.06x=0.12

x=0.12/-0.06

x=-2

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