37/37(6x-2x)-3(x-3x)+5(4x-12)=-4x+120

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Solution for 37/37(6x-2x)-3(x-3x)+5(4x-12)=-4x+120 equation:



37/37(6x-2x)-3(x-3x)+5(4x-12)=-4x+120
We move all terms to the left:
37/37(6x-2x)-3(x-3x)+5(4x-12)-(-4x+120)=0
Domain of the equation: 37(6x-2x)!=0
x∈R
We add all the numbers together, and all the variables
37/37(+4x)-3(-2x)+5(4x-12)-(-4x+120)=0
We multiply parentheses
37/37(+4x)+6x+20x-(-4x+120)-60=0
We get rid of parentheses
37/37(+4x)+6x+20x+4x-120-60=0
We multiply all the terms by the denominator
6x*37(+4x)+20x*37(+4x)+4x*37(+4x)-120*37(+4x)-60*37(+4x)+37=0
Wy multiply elements
222x^2(++740x^2(++148x^2(+-4440x(+-2220x(++37=0
We use the square of the difference formula
222x^2(+740x^2(+148x^2(-4440x(-2220x(+37=0

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