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9x-(5x-8)=2(2x+1)+6
We move all terms to the left:
9x-(5x-8)-(2(2x+1)+6)=0
We get rid of parentheses
9x-5x-(2(2x+1)+6)+8=0
We calculate terms in parentheses: -(2(2x+1)+6), so:We add all the numbers together, and all the variables
2(2x+1)+6
We multiply parentheses
4x+2+6
We add all the numbers together, and all the variables
4x+8
Back to the equation:
-(4x+8)
4x-(4x+8)+8=0
We get rid of parentheses
4x-4x-8+8=0
We add all the numbers together, and all the variables
=0
x=0/1
x=0
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