3x-4x+2+5x=6(x+1)+10

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Solution for 3x-4x+2+5x=6(x+1)+10 equation: 



3x-4x+2+5x=6(x+1)+10

We move all terms to the left:

3x-4x+2+5x-(6(x+1)+10)=0

We add all the numbers together, and all the variables

4x-(6(x+1)+10)+2=0



We calculate terms in parentheses: -(6(x+1)+10), so:

6(x+1)+10

We multiply parentheses

6x+6+10

We add all the numbers together, and all the variables

6x+16

Back to the equation:

-(6x+16)



We get rid of parentheses

4x-6x-16+2=0

We add all the numbers together, and all the variables

-2x-14=0

We move all terms containing x to the left, all other terms to the right

-2x=14

x=14/-2

x=-7

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